Difference between revisions of "20221106c2"
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(Created page with "<pre> 1: semaphore sem(1); int sum=0; queue q; void sumstop(int v): if i < 0: q.enqueue(v) sem.P() else i-- int sumgo(void): for each elem in q: int val=q.dequeu...") |
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counter = 0; | counter = 0; | ||
return counter | return counter | ||
+ | |||
+ | 13: (soluzione proposta su telegram) | ||
+ | |||
+ | #include <pthread.h> | ||
+ | |||
+ | #include "semaphore.h" | ||
+ | |||
+ | semaphore s; // semaforo che blocca le somme | ||
+ | semaphore finished; // semaforo che indica che le somme sono state fatte | ||
+ | semaphore critical_section; // sarà utilizzata per decidere chi entra nella critical section | ||
+ | |||
+ | volatile int sumstops = 0; | ||
+ | volatile int result; | ||
+ | |||
+ | void *sumstop(int v) { | ||
+ | semaphore_P(critical_section); | ||
+ | sumstops++; | ||
+ | semaphore_V(critical_section); | ||
+ | |||
+ | semaphore_P(s); | ||
+ | printf("summed %d\n", v); | ||
+ | result += v; | ||
+ | semaphore_V(finished); | ||
+ | } | ||
+ | |||
+ | |||
+ | int sumgo(void) { | ||
+ | semaphore_P(critical_section); // così sumstops è costante all'interno di questa section | ||
+ | result = 0; | ||
+ | for (int i = 0; i < sumstops; i++) { | ||
+ | semaphore_V(s); // permetti alla somma di andare | ||
+ | semaphore_P(finished); // aspetta che la somma sia finita prima di continuare | ||
+ | } | ||
+ | sumstops = 0; // reset number of blocked stops. | ||
+ | semaphore_V(critical_section); | ||
+ | return result; | ||
+ | } | ||
+ | |||
+ | void *run_sumgo(void) { | ||
+ | int res = sumgo(); | ||
+ | printf("the result found is %d\n", res); | ||
+ | printf("the result found is %d\n", result); | ||
+ | } | ||
+ | |||
+ | int main() { | ||
+ | srand(time(NULL)); | ||
+ | s = semaphore_create(0); | ||
+ | critical_section = semaphore_create(1); | ||
+ | finished = semaphore_create(0); | ||
+ | |||
+ | int n = rand() % 50; | ||
+ | pthread_t sumg, s[n]; | ||
+ | |||
+ | for (int i = 0; i < n; i++) { | ||
+ | pthread_create(&s[i], NULL, sumstop, i); | ||
+ | } | ||
+ | pthread_create(&sumg, NULL, run_sumgo, NULL); | ||
+ | |||
+ | for (int i = 0; i < 10; i++) { | ||
+ | pthread_join(s[i], NULL); | ||
+ | } | ||
+ | |||
+ | pthread_join(sumg, NULL); | ||
+ | } | ||
+ | |||
</pre> | </pre> |
Revision as of 14:01, 19 October 2022
1: semaphore sem(1); int sum=0; queue q; void sumstop(int v): if i < 0: q.enqueue(v) sem.P() else i-- int sumgo(void): for each elem in q: int val=q.dequeue() sum=sum + val return sum 2: queue values; semaphore s(0); int sum=0; void sumstop(int v): s.P() values.eqnueue(v) int sumgo(void): while !value.isEmpty(): s.V() mutex.P() sum=sum+values.dequeue() mutex.v() return sum 3: shared int sum=0; semaphore wait(0); semaphore mutex(1); void sumstop(int v): mutex.P(); sum = sum + v; mutex.V(); wait.P(); int sumgo(void): wait.V(); somma = sum; mutex.P() sum = 0 mutex.V() return somma; 4: queue<int> processlist; semaphore mutex(1); semaphore s(0); void sumstop(int v): mutex.P(); processlist.enqueue(v); mutex.P(); S.P(); int sumgo(void): int sum = 0; mutex.P(); while processlist.top() != NULL: sum += processlist.dequeue(); S.V(); mutex.V() retutn sum; 5: int counter = 0; int sum = 0; semaphore mutex(1); semaphore blocked(0); void sumstop(int v): mutex.P(); sum+=v; counter++; mutex.V(); blocked.P(); int sumgo(void): mutex.P(); intret = sum; sum = 0; for (int i=0; i<counter; i++) blocked.V() counter = 0; mutex.V() return intret 6: int sum = 0; mutex = new semaphore(1); queue q; void sumstop(int v): mutex.P(); sum += v; sintpid = getpid(); suspend(pid); mutex.V(); int sumgo(void): mutex.P(); while !q.empty(): resume(q.dequeue()) int value = sum; sum = 0; return value; 7: int nP, nV = -1, 0; int somma = 0 int val[] semaphore mutex(1); semaphore s(0); void sumstop(int v): mutex.P() val[nP++].add[v] s.P() np-- v[0].delete int sumgo(void): mutex.P(); nV++ if nP > 0: s.V() for (int i=0; i<nV; i++) somma += val[i] nv-- else mutex.V() return somma 8: struct blocked { semaphore sem(0); int value = 0; }; semaphore mutex(1); list<blocked> procs = new list<blocked>(); void sumstop(int v): mutex.P() blocked bl = new blocked(); bl.value = v procs.add(bl) bl.sem.P() mutex.V() int sumgo(void): mutex.P(); int count = 0; foreach proc in procs: count += proc.value procs.remove(proc) proc.sem.V() mutex.V() return count; 9: semaphore s[] new sem(0) semaphore s1 new sem(0) int tot, waiting = 0; void sumstop(int v): waiting++ s[waiting - 1].P() waiting-- tot = tot + v if waiting == 0: s1.V() int sumgo(void): if waiting = 0: return 0 for (i = waiting -1; i == 0; i--) s[i].V() s1.P() // per aspettare che tutti abbiano fatto la somma return tot 10: int nw = 0 int currsum = 0 semaphore mutex(1) semaphore wait2go(0) void sumstop(int v): mutex.P() currsum += v; nw++; mutex.V() wait2go.P() if --nw > 0: wait2go.V() else mutex.V() int sumgo(void): mutex.P(); if mw == 0: mutex.V() return 0; int sum = cursum; cursum = 0; wait2go.V(); return sum 11: semaphore mutex(1); semaphore semwait(0); int sum=0; int wait=0; void sumstop(int v): mutex.P() wait++ sum += v; mutex.V() semwait.P() mutex.P() wait--; mutex.V() if wait > 0: semwait.V() int sumgo(void): if wait == 0: return 0 semwait.V(); while (wait > 0) {} int val = sum mutex.P() sum = 0; mutex.V() return val; 12: semaphore mutex(0) volatile int counter = 0 void sumstop(int v): counter = counter + v; mutex.P() int sumgo(void): int val = counter; while (mutex.value != 0) mutex.V() counter = 0; return counter 13: (soluzione proposta su telegram) #include <pthread.h> #include "semaphore.h" semaphore s; // semaforo che blocca le somme semaphore finished; // semaforo che indica che le somme sono state fatte semaphore critical_section; // sarà utilizzata per decidere chi entra nella critical section volatile int sumstops = 0; volatile int result; void *sumstop(int v) { semaphore_P(critical_section); sumstops++; semaphore_V(critical_section); semaphore_P(s); printf("summed %d\n", v); result += v; semaphore_V(finished); } int sumgo(void) { semaphore_P(critical_section); // così sumstops è costante all'interno di questa section result = 0; for (int i = 0; i < sumstops; i++) { semaphore_V(s); // permetti alla somma di andare semaphore_P(finished); // aspetta che la somma sia finita prima di continuare } sumstops = 0; // reset number of blocked stops. semaphore_V(critical_section); return result; } void *run_sumgo(void) { int res = sumgo(); printf("the result found is %d\n", res); printf("the result found is %d\n", result); } int main() { srand(time(NULL)); s = semaphore_create(0); critical_section = semaphore_create(1); finished = semaphore_create(0); int n = rand() % 50; pthread_t sumg, s[n]; for (int i = 0; i < n; i++) { pthread_create(&s[i], NULL, sumstop, i); } pthread_create(&sumg, NULL, run_sumgo, NULL); for (int i = 0; i < 10; i++) { pthread_join(s[i], NULL); } pthread_join(sumg, NULL); }